Hello all,
in the top level of my design I have described a port in the following way:
port : OUT std_logic := 'Z';
The logic which will drive this port in the future is not yet existent so I could think that the FPGA would show a high impedance output at that pin. Unfortunately I can see that the FPGA drives that pin to a clear '0'.
I have an external pull-up resistor in the line driven by that pin, which shows a correct '1' when the FPGA is not programmed.
First I thought that this could be due to the fact that my -g UnusedPin option is "Pull down" and, lacking any logic behind the pin more than the default 'Z' value, the ISE could consider that pin as unused IOB. I set this option to "float" but no difference could be appreciated.
It will also work if I define the port as:
port : OUT std_logic := '1';
which, by the way, is not legal for my hardware.
Can anybody give me a clue about this strange phenomen?
